VB.NET Stripe: Retrieve a File Upload

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Retrieves the details of an existing file object. Supply the unique file upload ID from a file creation request, and Stripe will return the corresponding transfer information.

Documentation: https://stripe.com/docs/api/curl#retrieve_file_upload

CURL Command

curl https://files.stripe.com/v1/files/file_1BnEEuGswQrCoh0XqB3XkqAg \
   -u STRIPE_SECRET_KEY:

VB.NET Example

Dim rest As New Chilkat.Rest
Dim success As Boolean

'  URL: https://files.stripe.com/v1/files/file_1BnEEuGswQrCoh0XqB3XkqAg
Dim bTls As Boolean = True
Dim port As Integer = 443
Dim bAutoReconnect As Boolean = True
success = rest.Connect("files.stripe.com",port,bTls,bAutoReconnect)
If (success <> True) Then
    Debug.WriteLine("ConnectFailReason: " & rest.ConnectFailReason)
    Debug.WriteLine(rest.LastErrorText)
    Exit Sub
End If


rest.SetAuthBasic("STRIPE_SECRET_KEY","")


Dim sbResponseBody As New Chilkat.StringBuilder
success = rest.FullRequestNoBodySb("GET","/v1/files/file_1BnEEuGswQrCoh0XqB3XkqAg",sbResponseBody)
If (success <> True) Then
    Debug.WriteLine(rest.LastErrorText)
    Exit Sub
End If


Dim jsonResponse As New Chilkat.JsonObject
jsonResponse.LoadSb(sbResponseBody)

Dim id As String
Dim object As String
Dim created As Integer
Dim filename As String
Dim purpose As String
Dim size As Integer
Dim type As String
Dim url As String

id = jsonResponse.StringOf("id")
object = jsonResponse.StringOf("object")
created = jsonResponse.IntOf("created")
filename = jsonResponse.StringOf("filename")
purpose = jsonResponse.StringOf("purpose")
size = jsonResponse.IntOf("size")
type = jsonResponse.StringOf("type")
url = jsonResponse.StringOf("url")

Sample JSON Response Body

{
  "id": "file_1BnEEuGswQrCoh0XqB3XkqAg",
  "object": "file_upload",
  "created": 1516661888,
  "filename": "path",
  "purpose": "sigma_scheduled_query",
  "size": 500,
  "type": "csv",
  "url": "https://stripe-upload-api.s3.amazonaws.com/uploads/file_1BnEEuGswQrCoh0XqB3XkqAg?AWSAccessKeyId=KEY_ID\u0026Expires=TIMESTAMP\u0026Signature=SIGNATURE"
}